def nth_fibo(n):
if n==0: return 0
if n==1: return 1
F = [None] * (n + 1)
F[0] = 0
F[1] = 1
for i in range(2, n + 1):
F[i] = F[i - 1] + F[i - 2]
return F[n]
n = 6
result = nth_fibo(n)
print(f"The {n}th Fibonacci number is {result}")
#Python